document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163932>Question 1163932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if three cards are selected at random from a standard deck of 52 cards without replacement. find the probability of the following events.<BR>\n" );
document.write( "a. all cards are red<BR>\n" );
document.write( "b. atleast two cards are red<BR>\n" );
document.write( "all cards have the same suit </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788214 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (26/52)(25/51)(24/50)for the first<BR>\n" );
document.write( "this is 1/2*25/51*12/25<BR>\n" );
document.write( "=0.1176<BR>\n" );
document.write( "This is also (26C3)/52C3)\r<BR>\n" );
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document.write( "two cards are red at least.<BR>\n" );
document.write( "that is 2 or 3. We know 3<BR>\n" );
document.write( "two is 26C2*26C1/52C3<BR>\n" );
document.write( "=0.3824 probability  ANSWER<BR>\n" );
document.write( "Notice that the sum is 0.5000, and for the same with the colors reversed would be 0.5000\r<BR>\n" );
document.write( "\n" );
document.write( "Same suit is 4*13C3/52C3<BR>\n" );
document.write( "this is 0.0518<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );