document.write( "Question 1163948: Question: The sum of the first two terms of a decreasing geometric series is 5/4, and the sum to infinity is 9/4. Write the first three terms of the geometric series.\r
\n" ); document.write( "\n" ); document.write( "I solved it. I dont need the answer. It was tedious, which is ok if that is the way to do it. But I need to know whether I am making it tedious because the way I approached it and whether I am missing another easier way to solve it! \r
\n" ); document.write( "\n" ); document.write( "The way I solved it was:
\n" ); document.write( "a + ar = 5/4 (1)
\n" ); document.write( "a/(1-r) = 9/4 (2)\r
\n" ); document.write( "\n" ); document.write( "Subtracting (1) - (2) gave me ar^2 (the third term) = 3/2
\n" ); document.write( "Dividing (1)/(2) gave me r= +/- (2/3) and in turn plugging the values gave me a=3/4.
\n" ); document.write( "(Then I realized that there was no need for the tedious subtraction!!)\r
\n" ); document.write( "\n" ); document.write( "Also can I assume 'dividing the sum of a geometric series by its sum to infinity will always yield r^2 '\r
\n" ); document.write( "\n" ); document.write( "Thank you\r
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Algebra.Com's Answer #788207 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "The th partial sum of a geometric sequence is given by:\r
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\n" ); document.write( "\n" ); document.write( "Then, given that , dividing the partial sum by the infinite sum:\r
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\n" ); document.write( "\n" ); document.write( "yields\r
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\n" ); document.write( "\n" ); document.write( "Which is consistent with your calculations, that is you got from which you got using the partial sum .\r
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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