document.write( "Question 1163952: 2 people walk towards each other on a road. It takes the first person 2 hours to walk the road, it takes the 2nd person 3 hours to walk the road. When they meet, the first person walked 4 and 4/5 of a mile more than the 2nd person. How long is the road? \n" ); document.write( "

Algebra.Com's Answer #788199 by htmentor(1343) $\"\"$ $\"About$

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The first person's speed is s1 = d/2 (mi/h) where d is the total length of the road
\n" ); document.write( "The second person's speed is s2 = d/3 (mi/h)
\n" ); document.write( "The first person has walked a distance of d/2 + 4 4/5 when they meet
\n" ); document.write( "The second person has walked a distance of d/2 - 4 4/5 when they meet
\n" ); document.write( "Since they both walk for the same time, we can set the times equal to each other:
\n" ); document.write( "time = distance/speed
\n" ); document.write( "(d/2 + 4 4/5)/(d/2) = (d/2 - 4 4/5)/(d/3)
\n" ); document.write( "Solve for d: d + 48/5 = 3d/2 - 72/5
\n" ); document.write( "d/2 = 120/5 -> d = 48 mi \n" ); document.write( "

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