document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163925>Question 1163925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rocket beigns from rest and accelerates upward at +0.5m/s^2.<BR>\n" );
document.write( "a) At what time will the rocket reach a height of 1000 m?<BR>\n" );
document.write( "b) What will be the rocket's velocity at that point?\r<BR>\n" );
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document.write( "**BTW the answer for part a is supposed to be 63 s and the answer for part b is supposed to be +32m/s... could you show me the appraoch to getting to those answers! thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788168 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788168\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The height h, is given by:<BR>\n" );
document.write( "h = v0*t + 1/2a*t^2<BR>\n" );
document.write( "Since v0 = 0, we have h = 1/2a*t^2<BR>\n" );
document.write( "t = sqrt(2h/a) = sqrt(2000/0.5) = 63.25 ~ 63 s<BR>\n" );
document.write( "For the final velocity use v1 = v0 + at -> v1 = 0.5*63.25 = 31.62 ~ 32 m/s </SPAN>\n" );
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