document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163904>Question 1163904</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It has been estimated that there is 4.00 × 10^-4 mg of gold per liter of seawater. At price of $19.40/g, what would be the value of the gold in  9.87  km3 (1 km3 = 1 × 10^15 cm3) of the ocean? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #788166 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=788166\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9.87%2Akm%5E3%2A%2810%5E15%29%28cm%5E3%2Fkm%5E3%29%2A%281%2F1000%29%28L%2Fcm%5E3%29 ALIGN=MIDDLE  ALT=\"9.87%2Akm%5E3%2A%2810%5E15%29%28cm%5E3%2Fkm%5E3%29%2A%281%2F1000%29%28L%2Fcm%5E3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >-----------which will give the number of liters of seawater.   Can you continue from here? </SPAN>\n" );
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