document.write( "Question 108063This question is from textbook mathmatics a
\n" ); document.write( ": find three consecutive odd integers such that the largest decreased by three times the second is 47 less than the smallest
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Algebra.Com's Answer #78816 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Just write what it says:
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\n" ); document.write( "\"find three consecutive odd integers\":
\n" ); document.write( " x, (x+2, (x+4)
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\n" ); document.write( "\"the largest decreased by three times the second is 47 less than the smallest\":
\n" ); document.write( "(x+4) - 3(x+2) = x - 47
\n" ); document.write( ":
\n" ); document.write( "x + 4 - 3x - 6 = x - 47
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\n" ); document.write( "-2x - 2 = x - 47
\n" ); document.write( ":
\n" ); document.write( "x - 3x - x = -47 + 2
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\n" ); document.write( "-3x = -45
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\n" ); document.write( "x = -45/-3
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\n" ); document.write( "x = +15, 17, and 19 are the 3 odd integers
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\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "\"largest decreased by three times the second is 47 less than the smallest\"
\n" ); document.write( "19 - 3(17) = 15 - 47
\n" ); document.write( "19 - 51 = -32; confirms our solution \n" ); document.write( "

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