document.write( "Question 1163881: Three of the exterior angles of an n-sided polygon are 50°each, two of its iterior angles are 127° and 135°,and the remaining interior angles are 173°each. Find the value of n. \n" ); document.write( "
Algebra.Com's Answer #788141 by MathTherapy(10551)\"\" \"About 
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Three of the exterior angles of an n-sided polygon are 50°each, two of its iterior angles are 127° and 135°,and the remaining interior angles are 173°each. Find the value of n.
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Since 3 of the exterior angles are 50o each, these sum to 150o (50 * 3). So, n - 3 angles remain.
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document.write( "Since 2 interior angles are 127o and 135o each, their exterior angles are 53o and 45o, respectively. So, n - 3 - 2, or n - 5 angles remain.
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document.write( "Since remaining n - 5 INTERIOR angles are 173o each, then remaining n - 5 EXTERIOR angles are 7o (180 - 173) each, and total 7(n - 5), or (7n - 35)o
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document.write( "Since the sum of the exterior angles of any polygon, is 360o, we now get: 150 + 53 + 45 + 7n - 35 = 360
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document.write( "213 + 7n = 360
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document.write( "7n = 360 - 213
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document.write( "7n = 147
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document.write( "Number of sides, or \"highlight_green%28matrix%281%2C5%2C+n%2C+%22=%22%2C+147%2F7%2C+or%2C+21%29%29\" \n" );
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