document.write( "Question 1163881: Three of the exterior angles of an n-sided polygon are 50°each, two of its iterior angles are 127° and 135°,and the remaining interior angles are 173°each. Find the value of n. \n" ); document.write( "
Algebra.Com's Answer #788122 by Theo(13342)\"\" \"About 
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the sum of the exterior angles of a polygon is always 360.
\n" ); document.write( "you have 3 exterior angles of 50 degrees = 150 degrees.
\n" ); document.write( "each exterior angle of a polygon is supplemental to its corresponding interior angle.
\n" ); document.write( "you have one interior angle of 127 degrees subtracted from 180 degrees equals one exterior angle of 53 degrees
\n" ); document.write( "you have one interior angle of 135 degrees subtracted from 180 degrees equals one exterior angle of 45 degrees.
\n" ); document.write( "altogether, you have 5 exterior angles with a sum of 248 degrees.
\n" ); document.write( "since the sum of all the exterior angles must be equal to 360 degrees, you have 360 - 248 = 112 degrees missing.
\n" ); document.write( "since the remaining interior angles are 173 degrees each, then the remaining exterior angle has to be 180 - 173 = 7 degrees each.
\n" ); document.write( "therefore, 112 / 7 = 16 exterior angles missing.
\n" ); document.write( "the total number of exterior angles is therefore 5 plus 16 = 21, bringing the total number of exterior angles degrees equal to 248 plus 112 = 360.
\n" ); document.write( "the value of n therefore has to be 16 plus 5 = 21.\r
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\n" ); document.write( "\n" ); document.write( "it doesn't matter how many sides the polygon has; the sum of the exterior angles is always 360.\r
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