document.write( "Question 1163802: Hours before tickets for a rock concert were to
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document.write( "go on sale, people were lined up to buy tickets.
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document.write( "In fact, the first person came 12 hours before
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document.write( "the ticket booth was to open. A new group of
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document.write( "ticket buyers joined the line every 30 minutes.\r
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document.write( "a. If each new group has two persons more than
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document.write( "the previous group, how many people were
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document.write( "in line after the 20th group joined?\r
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document.write( "b. How many people were in line 3 hours
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document.write( "before the ticket booth opened?\r
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Algebra.Com's Answer #788055 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! The number of people in each group can be represented by an arithmetic progression, with the first term equal to 1 \n" ); document.write( "and the common difference equal to 2. \n" ); document.write( "The nth term of the progression is: a_n = 1 + 2(n-1) \n" ); document.write( "Thus in the 20th group, there are a_20 = 1 + 2(19) = 39 people \n" ); document.write( "The total number of people is the cumulative sum which is given by: \n" ); document.write( "S_n = (n/2)*(a_1 + a_n) -> S_20 = 10*(1 + 39) = 400 \n" ); document.write( "3 hours before, there are a total of 2*9 = 18 groups in line \n" ); document.write( "S_18 = 9*(1+35) = 324 \n" ); document.write( " |