document.write( "Question 108128: MARTINA LEAVES HOME AT 9 A.M. BICYCLING AT A RATE OF 24 MI/H.
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document.write( "TWO HOURS LATER JOHN LEAVES DRIVING AT THE RATE OF 48 MI/H.
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document.write( "AT WHAT TIME WILL JOHN CATCH UP WITH MARTINA?
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document.write( "THANKS
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document.write( "JMS \n" );
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Algebra.Com's Answer #78800 by checkley71(8403) ![]() You can put this solution on YOUR website! ASSUMING THEY ARE GOING IN THE SAME DIRECTION THEN: \n" ); document.write( "24T=48(T-2) \n" ); document.write( "24T=48T-96 \n" ); document.write( "24T-48T=-96 \n" ); document.write( "-24T=-96 \n" ); document.write( "T=-96/-24 \n" ); document.write( "T=4 HOURS AFTER 9 THEY WILL MEET. \n" ); document.write( "PROOF. \n" ); document.write( "24*4=48*2 \n" ); document.write( "96=96 \n" ); document.write( " \n" ); document.write( " |