document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163744>Question 1163744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plot of land is bounded by a 140-degree circular arc and two 80-foot radii of the samecircle.  Find the perimeter of the plot, as well as its area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #787943 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=787943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "140/360 = length of arc/pi x diameter<BR>\n" );
document.write( "140/360 = length of arc/ pi x 160<BR>\n" );
document.write( "length of arc = (140 x 160)/360<BR>\n" );
document.write( "length of arc = 62.22 ft (2 decimal places)<BR>\n" );
document.write( "Perimeter of field = 62.22 + 80 + 80 = 222.22 ft.<BR>\n" );
document.write( "140/360 = Area of sector/pi x radius^2<BR>\n" );
document.write( "140/360 = Area of sector/pi x 80^2<BR>\n" );
document.write( "(140 x 80^2)/360 = area of sector<BR>\n" );
document.write( "area of sector = 2488.89 ft^2  (2 decimal places)\r<BR>\n" );
document.write( "\n" );
document.write( "Perimeter of plot = 222.22 ft.<BR>\n" );
document.write( "Area of plot = 2488.89 ft^2<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );