document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163753>Question 1163753</A>: <I><SPAN STYLE=\"word-break: break-all;\">   How many cubic feet of grain would an octagonal silo hold if itwere 12 feet tall and had a regular base with 10-foot edges? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #787932 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=787932\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The volume is the area of the base, multiplied by the height.<br><BR>\n" );
document.write( "Look up (on the internet, or elsewhere) the formula for the area of a regular octagon in terms of the length of each side.<br><BR>\n" );
document.write( "(Note, on the other hand, it would be a good exercise for you to derive that formula yourself.  One way to start on that derivation is to view the regular octagon as a square with isosceles right triangles cut off each corner.)<br><BR>\n" );
document.write( "Use that and the given height to find the volume.<br><BR>\n" );
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