document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163731>Question 1163731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An executive invests $21,000, some at 8% and the rest at 6% Annual interest. if he receive an annual return of &1,620, how much is invested at each rate <BR>\n" );
document.write( "At 8% interest =<BR>\n" );
document.write( "At 6% interest = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #787924 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=787924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a formal algebraic solution is not required, here is a quick and easy solution method.<br><BR>\n" );
document.write( "(1) All $21,000 at 6% would yield $1260 interest; all at 8% would yield $1680 interest.<BR>\n" );
document.write( "(2) The actual interest, $1620, is 6/7 of the way from $1260 to $1680.  (Picture the three numbers on a number line -- 1260, 1620, and 1680.  1260 to 1680 is 420; 1260 to 1620 is 360; 360/420 = 6/7.)<BR>\n" );
document.write( "(3) That means 6/7 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 6/7 of the $21,000, or $18,000, was invested at 8%; the other $3000 was invested at 6%.<br><BR>\n" );
document.write( "CHECK: .06(3000)+.08(18000) = 180+1440 = 1620<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );