document.write( "Question 108127: Ann is 6 years older than Mary. She is also twice as old as Mary was when Ann was as old as Mary is now. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #78785 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
If \"Ann=x-years-old\" => \r
\n" ); document.write( "\n" ); document.write( "And \"Mary=y-years-old\"\r
\n" ); document.write( "\n" ); document.write( "Then:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+y%2B6\"...because Ann is \"6\" years older than Mary.
\n" ); document.write( "and
\n" ); document.write( "\"x=2y-6\"....She is also \"twice\" as old as Mary was when \"Ann-+was-+as+-old-+as-+Mary-+is+-now\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "use these two equations above to solve the problem:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "since the left sides of the equations above are equal, and then right sides must be equal too:\r
\n" ); document.write( "\n" ); document.write( "\"y%2B6+=+2y-6\"\r
\n" ); document.write( "\n" ); document.write( "\"y+%2B+6+=+2y-6+\"….move \"y+\"\r
\n" ); document.write( "\n" ); document.write( "\"6+%2B6=+2y-y\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+12\"……….. Mary is\"12-years-old\"
\n" ); document.write( " Then ………………......Ann is \"18-years-old\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "Ann is \"18\", Mary is \"12\" => Ann is \"6\" years older then Mary or\"12+%2B6=18\"\r
\n" ); document.write( "\n" ); document.write( "When \"Ann\" was as old as \"Mary\" is now, means it was before \"6\" \r
\n" ); document.write( "\n" ); document.write( "years \r
\n" ); document.write( "\n" ); document.write( "and before \"6\" years Ann was \"18-6=12\" and Mary was \"12-6+=+6\"\r
\n" ); document.write( "\n" ); document.write( "When Ann was \"12\", she was twice as old as Mary (\"2%2A6=12\").
\n" ); document.write( "
\n" ); document.write( "
\n" );