document.write( "Question 1163638: Please help me solve this problem. I tried to do it all different ways and am completely stumped.\r
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document.write( "Solve the following system of equations for the unknown variables.
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document.write( "3x + 3y = 3\r
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document.write( "-3x - 2z = -11\r
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document.write( "y + z = -1\r
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document.write( "(NOTE: Show answer in the following format (#,#,#), using the parentheses in your answer. If not entered in this format, will be scored incorrect.) \n" );
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Algebra.Com's Answer #787789 by Theo(13342) You can put this solution on YOUR website! your equations are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 3y = 3 \n" ); document.write( "-3x - 2z = -11 \n" ); document.write( "y + z = -1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for z in the third equation to get z = -y - 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace z in the second equation to get -3x - 2 * (-y-1) = -11. \n" ); document.write( "simplify to get -3x + 2y + 2 = -11 \n" ); document.write( "subtract 2 from both sides of the equation to get -3x + 2y = -13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can now solve the first 2 equations simultaneously. \n" ); document.write( "they are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 3y = 3 \n" ); document.write( "-3x + 2y = -13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "add the equations together to get: \n" ); document.write( "5y = -10 \n" ); document.write( "solve for y to get y = -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace y with -2 in the first equation to get: \n" ); document.write( "3x + 3y = 3 becomes 3x - 6 = 3 \n" ); document.write( "add 6 to both sides of that equation to get 3x = 9 \n" ); document.write( "solve for x to get x = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you now have x = 3 and y = -2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "go back to the third equation and replace y with -2 \n" ); document.write( "y + z = -1 becomes -2 + z = -1 \n" ); document.write( "add 2 to both sides of that equation to get z = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you now have x = 3 and y = -2 and z = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "go back to youor 3 original equations and replace x and y and z with their respective values to see if those equations are true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 3y = 3 becomes 3*3 - 3*2 = 3 which becomes 9 - 6 = 3 which becomes 3 = 3 which is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3x - 2z = -11 becomes -3*3 - 2*1 = -11 which becomes -9 - 2 = -11 which becomes - 11 = -11 which is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y + z = -1 bcomes -2 + 1 = -1 which becomes -1 = -1 which is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it looks like x = 3, y = -2, z = 1 is your solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it can be shown in (x,y,z) format as (3,-2,1)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |