document.write( "Question 1163591: 2m + n = 0
\n" ); document.write( "m + 2n = 3 \n" ); document.write( "
Algebra.Com's Answer #787729 by Alan3354(69443)\"\" \"About 
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2m + n = 0
\n" ); document.write( "m + 2n = 3
\n" ); document.write( "--------------
\n" ); document.write( "If you want to solve for m & n, you should say that.
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\n" ); document.write( "2m + n = 0
\n" ); document.write( "m + 2n = 3
\n" ); document.write( "------
\n" ); document.write( "1 method is substitution:
\n" ); document.write( "n = -2m
\n" ); document.write( "Sub for n in the 2nd eqn
\n" ); document.write( "m + 2*(-2m) = 3
\n" ); document.write( "m - 4m = 3
\n" ); document.write( "-3m = 3
\n" ); document.write( "m = -1
\n" ); document.write( "----
\n" ); document.write( "n = -2m = +2
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\n" ); document.write( "Another method is elimination:
\n" ); document.write( "2m + n = 0
\n" ); document.write( "m + 2n = 3
\n" ); document.write( "---
\n" ); document.write( "Multiply the 1st eqn by 2:
\n" ); document.write( "4m + 2n = 0
\n" ); document.write( "m + 2n = 3
\n" ); document.write( "--------------------- Subtract
\n" ); document.write( "3m = -3
\n" ); document.write( "m = -1
\n" ); document.write( "etc\r
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