document.write( "Question 1163545: Determine the intervals of concavity and state any points of inflection.\r
\n" ); document.write( "\n" ); document.write( "\"+f%28x%29+=+%281%2F6%29x%5E4+-+%287%2F6%29x%5E3+%2B+%283%2F2%29x%5E2+-+8x+%2B+10+\".
\n" ); document.write( "

Algebra.Com's Answer #787668 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " First derivative\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Second derivative\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "----------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solve for x to find the two solutions x = 1/2 and x = 3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug in a value to the left of x = 1/2, say x = 0, to find that is a positive value (the result is positive 3 when you use x = 0), so is positive on the interval meaning f(x) is concave up on this interval.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug in some number between x = 1/2 and x = 3. I'll use x = 1. If you plug x = 1 into the second derivative function, you should get a negative result. This means is negative throughout the interval and f(x) is concave down on this interval.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Lastly, f(x) is concave up on the interval because plugging in a value to the right of x = 3, say x = 4, leads to being positive.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Because there is a sign change of as we pass through the roots x = 1/2 and x = 3, this means we have points of inflection at these x values. Plug those x values one at a time into f(x) to find the corresponding y coordinates are y = 6.23958 (approx) and y = -18.5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The points of infection are (1/2, 6.23958) and (3, -18.5)
\n" ); document.write( "
\n" );