document.write( "Question 1163519: Question: I always thought, till now, that the number of possible roots for a polynomial is equal(or atmost) to its highest degreee. Also I have been counting each radical and complex root as two since they all have +/- values (just like +/- n will be counted as two). Then I came across the following polynomials (degree four and five):
\n" ); document.write( " 4X^4 +8X^3 -5X^2 -2X +1 = 0
\n" ); document.write( " 3X^5 +2X^4 -15X^3 -10X^2 +12X +8 = 0
\n" ); document.write( "The second one as expected has 5 roots: +/-1, +/-2, -2/3
\n" ); document.write( "But the first one which (degree-4) has FIVE roots! viz., +/-1/2, +/-√2 and -1.\r
\n" ); document.write( "\n" ); document.write( "So which of assumption is wrong?
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Algebra.Com's Answer #787632 by ikleyn(52803)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "It is a  reminiscence  of the  Rational root theorem  in your mind.\r
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\n" ); document.write( "\n" ); document.write( "The  Rational root theorem  says that all the rational roots of a polynomial with integer coefficients\r
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\n" ); document.write( "\n" ); document.write( "are among the fractions   +/- \"p%2Fq\",  where  q  is a divisor of the leading coefficient and  p  is a divisor of the constant term.\r
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\n" ); document.write( "\n" ); document.write( "But this theorem  DOES  NOT  state \r
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document.write( "    a)  NEITHER  that all the roots of a polynomial are among these fractions\r\n" );
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document.write( "                 (irrational possible roots are DEFINITELY out of this set; complex roots ALSO are out of this set)\r\n" );
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document.write( "    b)  NOR      that each root goes two times with the \" + \"  and  \" - \" sign.\r\n" );
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\n" ); document.write( "\n" ); document.write( "About this theorem, read this Wikipedia article \r
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\n" ); document.write( "\n" ); document.write( "https://en.wikipedia.org/wiki/Rational_root_theorem\r
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\n" ); document.write( "\n" ); document.write( "and have fan (!)\r
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