document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108109>Question 108109</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Paul and Charlene are 420 miles apart.  They start toward each other with Paul driving 16 mi/h faster than Charlene.  They meet in 5 hours.  Find Charlene's speed. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78755 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let C be Charlene's rate<BR>\n" );
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document.write( "Since Paul's rate is 16 mph more than C, then we can write that Paul's rate is C + 16.<BR>\n" );
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document.write( "The distance each travels is their rate times the time that they drive at their rate. That <BR>\n" );
document.write( "means that Charlene travels C*T miles. But T is given as 5 hours. Therefore, the distance that<BR>\n" );
document.write( "Charlene travels in the 5 hours is 5*C. Meanwhile, Paul's rate times the time that he travels<BR>\n" );
document.write( "at that rate is (C + 16)*T, and since T = 5 hours, the distance that Paul travels is 5*(C + 16).<BR>\n" );
document.write( "This multiplies out to a distance of 5C + 80.<BR>\n" );
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document.write( "The problem says that the total distance that is to be covered by the two drivers is <BR>\n" );
document.write( "420 miles. In equation form, the sum of the distances covered by the two drivers is:<BR>\n" );
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document.write( "5C + 5C + 80 = 420<BR>\n" );
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document.write( "Add the two terms on the left side that contain C to get:<BR>\n" );
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document.write( "10C + 80 = 420<BR>\n" );
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document.write( "Get rid of the 80 on the left side by subtracting 80 from both sides to get:<BR>\n" );
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document.write( "10C = 420 - 80 = 340<BR>\n" );
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document.write( "Solve for C (Charlene's rate) by dividing both sides by 10 to get<BR>\n" );
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document.write( "C = 340/10 = 34 mph<BR>\n" );
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document.write( "You were asked to find Charlene's speed, and you have it .... 34 mph. [Paul's rate is 16<BR>\n" );
document.write( "mph faster, so Paul drives at 50 mph.]<BR>\n" );
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document.write( "Hope this helps you to understand the problem and to see how to find the solution.<BR>\n" );
document.write( ".\r<BR>\n" );
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document.write( " </SPAN>\n" );
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