document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107997>Question 107997</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tell wether the number is prime or composite. If it is composite,write its prime factorization.\r<BR>\n" );
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document.write( "<b> 8. 345\r<BR>\n" );
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document.write( "Any help with this equation would be GREATLY appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78752 by </B><A HREF=/tutors/aboutme.mpl?userid=rhissam><B>rhissam(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rhissam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "If any # can divide into 345 evenly then 345 has to be a composite number. The word composite is like compound, a compound sentence has more than one idea, and a composite number has more factors than just 1 and the # itself. Since 345 ends in a 5, then 5 will divide into 345 evenly. Also, if you add the digits of 345: 3+4+5 =12 and 12 is a multiple of 3, then we know 3 will also divide evenly into 345 which proves it is truly a composite number. </SPAN>\n" );
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