document.write( "Question 1163396: A radioactive substance decays so that after t years, the amount remaining,
\n" ); document.write( "expressed as a percent of the original amount, is \"A%28t%29+=+100%281.5%29%5E%28-t%29\"
\n" ); document.write( "Determine the rate of decay after 2 years. Round to 2 decimal places.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #787477 by ikleyn(52932)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Exponential rate of decay per year \"r\" remains THE SAME during the entire decay process \r\n" );
document.write( "\r\n" );
document.write( "(i.e. FOREVER, or, more precisely, until the last radioactive atom decayed :-).\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It is equal to  r = \"1.5%5E%28-1%29\" = \"1%2F1.5\" = \"1%2F%28%283%2F2%29%29\" = \"2%2F3\" = 0.666666...  or  66.6666%  of the mass per year.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "By the way, when you formulate a problem like this one, you should tell in your question, which rate of decay do you mean:\r\n" );
document.write( "\r\n" );
document.write( "    exponential coefficient of decay or linear coefficient at the given time.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "These are two different values and two different conceptions.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Without clarification, the meaning of the question is dark / unclear.\r\n" );
document.write( "
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "/\/\/\/\/\/\/\/\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "What the tutor ankor@dixie-net.com wrote in his response,  was not an answer to your question.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "It was something   V E R Y   different.   It was about the remained mass amount after 2 years.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "On radioactive decay problems,  see the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Radioactive decay problems \r
\n" ); document.write( "\n" ); document.write( "in this site.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );