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document.write( " I will assume that they started from the same point SIMULTANEOUSLY \r
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document.write( " (although the post missed this important condition).\r
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document.write( "Let L be the circumference of the circle.\r\n" );
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document.write( "Then the faster cyclist will catch the slower cyclist first time when the faster cyclist will cover \r\n" );
document.write( "the distance which exactly 1 circumference longer than the distance covered by the slower cyclist \r\n" );
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document.write( " 9t - 5t = L.\r\n" );
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document.write( "It gives the time to get first meeting point\r\n" );
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document.write( " t =
=
hours\r\n" );
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document.write( "and the distance which the faster cyclist covered during this time is\r\n" );
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= 9t =
miles.\r\n" );
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document.write( "The distance which the slower cyclist covered during this time is \r\n" );
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= 5t =
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document.write( "The meeting point is geometrically the same point on the circle for both cyclists,
, \r\n" );
document.write( "and its angle measure on the circle is\r\n" );
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=
=
=
of the full angle of
radians, or 90 degrees.\r\n" );
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document.write( "So, they started simultaneously, and their first meeting point is at the 90 degrees angle.\r\n" );
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document.write( "Next, they started from this point SIMULTANEOUSLY and . . . and everything was repeated.\r\n" );
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document.write( "Hence, their next meeting point is the point on the circle with the angle of 180 degrees.\r\n" );
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document.write( " It can be proved using strict mathematical arguments, but it should be ABSOLUTELY CLEAR to you without any arguments.\r\n" );
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document.write( "So, there are 4 remarkable points on the circle: first point is the starting point, and 3 other points \r\n" );
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document.write( "(the points where whey meet/catch each other) are the images of the starting point, rotated 90°, 180°, and 270° along the circle.\r\n" );
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document.write( "ANSWER. There are 4 points on the circle, where the faster cyclist catches the slower cyclist.\r\n" );
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document.write( "Solved.\r
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document.write( "Pretty amazing and unexpected result (!)\r
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