document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163298>Question 1163298</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Students who score in the top 10 percent are recognized publicly for their achievement by the Department of the Treasury. Assuming a normal distribution, how many standard deviations above the mean does a student have to score to be publicly recognized? (Round your answer to 2 decimal places.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #787355 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=787355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "You'll need to use a calculator or a table. I recommend a calculator. I'm using <a  rel=nofollow HREF= \"http://www.davidmlane.com/hyperstat/z_table.html\">this one</a> here. You can use any (online) resource that you find preferable. \r<BR>\n" );
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document.write( "If you use the calculator I posted, then click the button that says \"Value from an area\". Type in 0.10 for the area. Leave the mean and standard deviation as they are (0 and 1 respectively). Click the button labeled \"above\" to have the value 1.282 show up. You may need to click the \"recalculate\" button.\r<BR>\n" );
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document.write( "This means P(Z > 1.282) = 0.10 approximately. So 10% of the population is above z = 1.282; when rounding to two decimal places, we get z = 1.28\r<BR>\n" );
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document.write( "We are approximately 1.28 standard deviations above the mean. A positive z score means we are above the mean z = 0, a negative score means we're below the mean. The absolute value of the z score tells us the distance from the mean.\r<BR>\n" );
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document.write( "If you are using a Texas Instruments (TI) calculator, such as a TI83, then press the key labeled \"2ND\" and then press the VARS key. <BR>\n" );
document.write( "Scroll down to option 3.<BR>\n" );
document.write( "Type in 0.90 and hit enter<BR>\n" );
document.write( "Your TI calculator should show invNorm(0.90) = 1.281551567 approximately. This shows P(Z < 1.281551567) = 0.90 which is equivalent to saying P(Z > 1.281551567) = 0.10\r<BR>\n" );
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document.write( "This leads to z = 1.282 and z = 1.28 as found earlier. \r<BR>\n" );
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document.write( "Answer: <font color=red>1.28 standard deviations above the mean</font><BR>\n" );
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