document.write( "Question 1163258: 2/5's of A's money is equal to 2/3's of B's money. Total of their money is $4800. Determine A and B's money.\r
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document.write( "2/5 of A's = 2/3's of B's.\r
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document.write( "A + B = 4800.\r
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document.write( "Not sure how to proceed.\r
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Algebra.Com's Answer #787308 by ikleyn(52803)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "From the condition, you have\r\n" ); document.write( "\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------- \n" ); document.write( "comment from student: Why did you multiply equation (3) by 3 ? \n" ); document.write( "-------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "My response : Good question, thanks for asking.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " I multiply equation (3) by 3 in order for to have this term \" 3A \", which I later replace by \" 5B \".\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " My secret goal is to get an equation for one unknown \" B \" only, and for it I make all these transformations.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Is everything clear to you now ?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you still have questions, do not hesitate to post them to me . . . \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Have a nice day (!)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------- \n" ); document.write( "comment from student: How did you get 3A = 5B from 6A = 10B ? \n" ); document.write( "-------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "My response : I divided both sides of the equation 6A = 10B by 2.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |