document.write( "Question 1163265: Two hundred and fifty passenger have mad reservations for airplane flight. If the probability that a passenger who has a reservation show up is 0.98. what is the exactly five that will not show up? \n" ); document.write( "
Algebra.Com's Answer #787306 by ikleyn(52786)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "It is  \"C%5B250%5D%5E5%2A%281-0.98%29%5E5%2A0.98%5E%28250-5%29\" = \"%28%28250%2A249%2A248%2A247%2A246%29%2F%281%2A2%2A3%2A4%2A5%29%29%2A0.02%5E5%2A0.98%5E245\" = 0.1772.    ANSWER\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "It is a binomial distribution problem \r\n" );
document.write( "\r\n" );
document.write( "with the number of trials n = 250 and the number of success trials of 245 = 250-5.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To see many other similar solved problems, look into the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Simple and simplest probability problems on Binomial distribution \r
\n" ); document.write( "\n" ); document.write( "    - Typical binomial distribution probability problems \r
\n" ); document.write( "\n" ); document.write( "in this site.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );