document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163258>Question 1163258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2/5's of A's money is equal to 2/3's of B's money.  Total of their money is $4800.  Determine A and B's money.\r<BR>\n" );
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document.write( "2/5 of A's = 2/3's of B's.\r<BR>\n" );
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document.write( "A + B = 4800.\r<BR>\n" );
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document.write( "Not sure how to proceed.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #787295 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=787295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> that's a good start<BR>\n" );
document.write( "multiply the first by 15 to clear fractions<BR>\n" );
document.write( "6A=10B<BR>\n" );
document.write( "3A=5B. then A=(5/3) B, to bring a fraction back which can be more easily substituted.<BR>\n" );
document.write( "A+B=4800<BR>\n" );
document.write( "(5/3)B+B=4800. (5/3)+B is (5/3)B+(3/3)B, common denominator. They add to (8/3)B<BR>\n" );
document.write( "(8/3)B=4800<BR>\n" );
document.write( "B=4800*3/8=$1800<BR>\n" );
document.write( "A=$3000\r<BR>\n" );
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document.write( "2/5 s of A is $1200<BR>\n" );
document.write( "2/3s of B is $1200<BR>\n" );
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