document.write( "Question 1163251: Pls help me. Given that logx^256=2 find log8^(1over x) Thanks \n" ); document.write( "
Algebra.Com's Answer #787286 by MathTherapy(10555)\"\" \"About 
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\n" ); document.write( "Pls help me. Given that logx^256=2 find log8^(1over lower x) Thanks
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If you meant: \"matrix%281%2C3%2C+log+%28x%2C+%28256%29%29%2C+%22=%22%2C+2%29\", then READ on!\r\n" );
document.write( "\"matrix%281%2C3%2C+x%5E2%2C+%22=%22%2C+256%29\" ------ Converting to EXPONENTIAL form\r\n" );
document.write( "\"matrix%282%2C3%2C+x%5E2%2C+%22=%22%2C+16%5E2%2C+x%2C+%22=%22%2C+16%29\" ------ EXPONENTS are equal and so are the BASES\r\n" );
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document.write( "Now, what's needed is: \"log+%28x%2C+%288%29%29\". If it's \"log+%288%2C+%28x%29%29\", then you're on your own, but should be able to figure it out, if you follow below!\r\n" );
document.write( "\"log+%2816%2C+%288%29%29\" -------- Substituting 16 for x\r\n" );
document.write( "\"matrix%281%2C3%2C+c%2C+%22=%22%2C+log+%2816%2C+%288%29%29%29\" --- Letting the value of \"log+%2816%2C+%288%29%29\" be \"c.\" \r\n" );
document.write( "\"matrix%281%2C3%2C+16%5Ec%2C+%22=%22%2C+8%29\" -------- Converting to EXPONENTIAL form\r\n" );
document.write( "\"matrix%282%2C3%2C+%282%5E4%29%5Ec%2C+%22=%22%2C+2%5E3%2C+2%5E%284c%29%2C+%22=%22%2C+2%5E3%29\" \r\n" );
document.write( "4c = 3 ------ BASES are equal and so are the EXPONENTS\r\n" );
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