document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=108022>Question 108022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write an equation of a line that is perpendicular to y= -3/4x + 2 and passes through (-4,1) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #78727 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=78727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THIS LINE HAS A SLOPE OF -3/4.<BR>\n" );
document.write( "THEREFORE A PERPENDICULAR LINE HAS A SLOPE OF 4/3.<BR>\n" );
document.write( "NOW REOPLACE THE X & Y VALUES IN THE LINE EQUATION [Y=mX+b] WITH (-4,1) & SOLVE FOR THE Y INTERCEPT (b).<BR>\n" );
document.write( "1=4/3*-4+b<BR>\n" );
document.write( "1=-16/3+b<BR>\n" );
document.write( "b=1+16/3<BR>\n" );
document.write( "b=(3+16)/3<BR>\n" );
document.write( "b=19/3 FOR THE Y INTERCEPT.<BR>\n" );
document.write( "Y=4X/3+19/3 ANSWER. </SPAN>\n" );
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