document.write( "Question 1163244: Hi\r
\n" ); document.write( "\n" ); document.write( "The sum of the ages of Ruth Selma and Tom is one year more than 3 times toms age.the sum of Tom and Selma ages is 2 years more than 3 times Ruth's age.
\n" ); document.write( "The sum of Ruth and toms ages is the same as the sum of selmas age and half of ruths age. How old is each one.\r
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Algebra.Com's Answer #787269 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "The sum of the ages of Ruth Selma and Tom is one year more than 3 times toms age.the sum of Tom and Selma ages is 2 years more than 3 times Ruth's age.
\n" ); document.write( "The sum of Ruth and toms ages is the same as the sum of selmas age and half of ruths age.
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document.write( "Ruth        r\r\n" );
document.write( "Selma       x\r\n" );
document.write( "Tom         t\r\n" );
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\n" ); document.write( "\n" ); document.write( "\"system%28r%2Bx%2Bt=1%2B3t%2Cx%2Bt=2%2B3r%2Cr%2Bt=x%2Br%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28r%2Bx-2t=1%2C-3r%2Bx%2Bt=2%2C2r%2B2t=2x%2Br%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%28r%2Bx-2t=1%2C3r-x-t=-2%2Cr-2x%2B2t=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "From here or earlier, methods can vary, but choosing E1+E3, this gives \"2r-x=1\". This means, \"x=2r-1\".\r
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\n" ); document.write( "\n" ); document.write( "Substituting for the expression for x,\r
\n" ); document.write( "\n" ); document.write( "\"system%28r%2B2r-1-2t=1%2C3r-2r%2B1-t=-2%2Cr-2%282r-1%29%2B2t=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%283r-2t=2%2Cr-t=-3%2Cr-4r%2B2%2B2t=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"system%283r-2t=2%2Cr-t=-3%2C-3r%2B2t=-2%29\"------------here, E1 and E3 are equivalent, so,...\r
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\n" ); document.write( "\n" ); document.write( "\"system%283r-2t=2%2Cr-t=-3%29\"\r
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