document.write( "Question 1163242: If 2 cars were 300 miles apart at 12 noon, and drove until they met each other at 3 pm, find the speeds of both cars. 1 car was driving at a speed of 10 mph faster then the other. \n" ); document.write( "
Algebra.Com's Answer #787268 by ikleyn(52778)\"\" \"About 
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document.write( "Let x be the rate of the slower car, in miles per hour;\r\n" );
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document.write( "then the rate of the faster car is (x+10) mph.\r\n" );
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document.write( "The total distance equation is then\r\n" );
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document.write( "    3x + 3*(x+10) = 300  miles   (the \"3\" here is \"3 hours from 12 noon to 3 pm).\r\n" );
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document.write( "From the equation,\r\n" );
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document.write( "    3x + 3x + 30 = 300\r\n" );
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document.write( "    6x           = 300 - 30 = 270\r\n" );
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document.write( "     x                      = 270/6 = 45.\r\n" );
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document.write( "ANSWER.  The slower car rate was  45 mph;  the faster car  45+10 = 55 mph.\r\n" );
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\n" ); document.write( "\n" ); document.write( "See introductory lessons on Travel and Distance problems\r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in opposite directions \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in the same direction (catching up)\r
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\n" ); document.write( "\n" ); document.write( "You will find the solutions of many similar problems there.\r
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\n" ); document.write( "\n" ); document.write( "Read them and learn once and for all from these lessons on how to solve simple Travel and Distance problems.\r
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\n" ); document.write( "\n" ); document.write( "Become an expert in this area.\r
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