document.write( "Question 1163219: If nPr = 336 and nCr = 56, find n and r. \r
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Algebra.Com's Answer #787242 by MathTherapy(10552) $\"\"$ $\"About$

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If nPr = 336 and nCr = 56, find n and r. \r
\n" ); document.write( "\n" ); document.write( "Please note that:
\n" ); document.write( "P and C are permutation and combination respectively.
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document.write( " ------ Substituting for   \r\n" );
document.write( " ------ Cross-multiplying\r\n" );
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document.write( ", since 3(2)(1) = 6\r\n" );
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document.write( "With r = 3, we can say that: \r\n" );
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document.write( "This means that there are 3 CONSECUTIVE, DESCENDING INTEGER-FACTORS of 336. These are: 8, 6, and 7\r\n" );
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document.write( "Therefore, we get:

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