document.write( "Question 1163170: Help me please \r
\n" ); document.write( "\n" ); document.write( "A spherical balloon is decreasing its volume at a rate of 163.87 cm3/min. Find the rate at which the radius is decreasing when the volume is 4916.12 cm3.\r
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Algebra.Com's Answer #787234 by Edwin McCravy(20063)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Instead of doing it for you, I'll do another one exactly like yours with the\r\n" );
document.write( "numbers changed.  I'll do this one:\r\n" );
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\n" ); document.write( "A spherical balloon is decreasing its volume at a rate of 274.98 cm³/min.
\n" ); document.write( "Find the rate at which the radius is decreasing when the volume is 5027.23
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document.write( "\"V+=+expr%284%2F3%29pi%2Ar%5E3\"\r\n" );
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document.write( "\"V+=+4.188790205r%5E3\"\r\n" );
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document.write( "When the volume is 5027.23 cm³, the radius is\r\n" );
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document.write( "\"5027.23+=+4.188790205r%5E3\"\r\n" );
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document.write( "\"5027.23%2F4.188790205=r%5E3\"\r\n" );
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document.write( "\"1200.162757=r%5E3\"\r\n" );
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document.write( "\"root%283%2C1200.162757%29=r\"\r\n" );
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document.write( "\"10.6270661=r\"\r\n" );
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document.write( "Now go back to the formula, allowing r and V to vary.\r\n" );
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document.write( "\"V+=+4.188790205r%5E3\"\r\n" );
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document.write( "\"dV%2Fdt=3%2A4.188790205r%5E2%2Aexpr%28dr%2Fdt%29\"\r\n" );
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document.write( "\"dV%2Fdt=12.56637062r%5E2%2Aexpr%28dr%2Fdt%29\"\r\n" );
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document.write( "Now substitute the values:\r\n" );
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document.write( "\"274.98=12.56637062%2810.6270661%29%5E2%2Aexpr%28dr%2Fdt%29\"\r\n" );
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document.write( "\"274.98=1419.177209%2Aexpr%28dr%2Fdt%29\"\r\n" );
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document.write( "\"274.98%2F1419.177209=dr%2Fdt\"\r\n" );
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document.write( "\"0.19376=dr%2Fdt\"\r\n" );
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document.write( "Answer for my problem: 0.19376 cm²/min\r\n" );
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document.write( "Now do yours.\r\n" );
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document.write( "Edwin

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