document.write( "Question 1163215: Hi\r
\n" ); document.write( "\n" ); document.write( "The sum of jans and bobs age is 18 years. When Jan is 3 years older than twice her present age, she will be 1.5 times as old as Bob will be in a year after that. \r
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Algebra.Com's Answer #787210 by AnlytcPhil(1807)\"\" \"About 
You can put this solution on YOUR website!
The sum of Jan's and Bob's age is 18 years.
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document.write( "J+B = 18\r\n" );
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\n" ); document.write( "When Jan is 3 years older than
\n" ); document.write( "twice her present age,
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document.write( "That will be in k years, so\r\n" );
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document.write( "J+k = 2J+3\r\n" );
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document.write( "Bob will then be B+k.\r\n" );
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\n" ); document.write( "She (Jan) will be 1.5 times as old as Bob will be in a year
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document.write( "J+k = 1.5(B+k+1)\r\n" );
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document.write( "\"system%28J%2BB=18%2CJ%2Bk=2J%2B3%2CJ%2Bk=1.5%28B%2Bk%2B1%29%29\"\r\n" );
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document.write( "B=3, J=15, k=18 \r\n" );
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document.write( "Edwin
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