document.write( "Question 1163137: A box contained 50Cents coins and 20 cents coins in the ratio 2:3.when I took out foor 50Cents coins, exchanged them for 20 cents coins. And then put the money back in the box, the ratio became 2:7. Find the sum of money in the box. \n" ); document.write( "
Algebra.Com's Answer #787172 by MathTherapy(10559)\"\" \"About 
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A box contained 50Cents coins and 20 cents coins in the ratio 2:3.when I took out foor 50Cents coins, exchanged them for 20 cents coins. And then put the money back in the box, the ratio became 2:7. Find the sum of money in the box.
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I agree with Tutor @IKLEYN. 
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document.write( "Although not stated, the four (4, NOT foor) 50c coins that were removed were NOT replaced with 4 20c coins.
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document.write( "The four 50c coins, with a value of $2 were replaced with 20c coins worth $2, and that's 10 20c coins.
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document.write( "By letting the multiplicative factor be x, we get: \"matrix%281%2C3%2C+%282x++-++4%29%2F%283x+%2B+10%29%2C+%22=%22%2C+2%2F7%29\", and subsequently, x = 6.
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document.write( "So, with the multiplicative factor being 6 - leading to 12 original 50c coins worth $6, and 18 original 20c coins worth $3.60 - the sum in box = \"highlight_green%28matrix%281%2C3%2C+6+%2B+3.60%2C+%22=%22%2C+%22%249.60%22%29%29\" \n" );
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