document.write( "Question 1163147: After seven years raj will be twice as old as he was three years ago what is his present age
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Algebra.Com's Answer #787132 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Using formal algebra....

\n" ); document.write( "x = current age
\n" ); document.write( "x+7 = age 7 years from now
\n" ); document.write( "x-3 = age 3 years ago

\n" ); document.write( "His age 7 years from now is (will be) twice his age 3 years ago:

\n" ); document.write( "\"x%2B7+=+2%28x-3%29\"

\n" ); document.write( "Solve using basic algebra. I leave that to you.

\n" ); document.write( "Solving the problem informally, using logical reasoning and simple mental arithmetic, can be good brain exercise. Something like the following.

\n" ); document.write( "The difference between 7 years from now and 3 years ago is 10 years.
\n" ); document.write( "If the age 7 years from now is twice the age 3 years ago, and the difference is 10 years, then those two ages must be 20 and 10.
\n" ); document.write( "So 7 years from now he will be 20, and 3 years ago he was 10; either way, his current age is 13.

\n" ); document.write( "You of course should get that same answer using the algebraic solution method.

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