document.write( "Question 1163147: After seven years raj will be twice as old as he was three years ago what is his present age
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #787132 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Using formal algebra.... \n" ); document.write( "x = current age \n" ); document.write( "x+7 = age 7 years from now \n" ); document.write( "x-3 = age 3 years ago \n" ); document.write( "His age 7 years from now is (will be) twice his age 3 years ago: \n" ); document.write( " \n" ); document.write( "Solve using basic algebra. I leave that to you. \n" ); document.write( "Solving the problem informally, using logical reasoning and simple mental arithmetic, can be good brain exercise. Something like the following. \n" ); document.write( "The difference between 7 years from now and 3 years ago is 10 years. \n" ); document.write( "If the age 7 years from now is twice the age 3 years ago, and the difference is 10 years, then those two ages must be 20 and 10. \n" ); document.write( "So 7 years from now he will be 20, and 3 years ago he was 10; either way, his current age is 13. \n" ); document.write( "You of course should get that same answer using the algebraic solution method. \n" ); document.write( " \n" ); document.write( " |