document.write( "Question 1163142: The sum of the ages of two brothers is 38 years 4 years ago the age of the Elder brother was the square of the younger Brothers age. Find their ages. \n" ); document.write( "
Algebra.Com's Answer #787125 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The sum of the ages of two brothers is 38 years. 4 years ago the age of the Elder brother was the square of the younger Brothers age. Find their ages. \n" ); document.write( "---------------- \n" ); document.write( "e + y = 38 now \n" ); document.write( "4 years ago, e + y = 30 \n" ); document.write( "----------- \n" ); document.write( "e + y = 30 \n" ); document.write( "e = y^2 \n" ); document.write( "---> 5 & 25 then \n" ); document.write( "9 & 29 now \n" ); document.write( "=============== \n" ); document.write( "The hard way: \n" ); document.write( "e + y = 30 \n" ); document.write( "e = y^2 \n" ); document.write( "y^2 + y - 30 = 0 \n" ); document.write( "(y+6)*(y-5) = 0 \n" ); document.write( "y = 5 \n" ); document.write( "etc \n" ); document.write( " |