document.write( "Question 1163142: The sum of the ages of two brothers is 38 years 4 years ago the age of the Elder brother was the square of the younger Brothers age. Find their ages. \n" ); document.write( "
Algebra.Com's Answer #787125 by Alan3354(69443)\"\" \"About 
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The sum of the ages of two brothers is 38 years. 4 years ago the age of the Elder brother was the square of the younger Brothers age. Find their ages.
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\n" ); document.write( "e + y = 38 now
\n" ); document.write( "4 years ago, e + y = 30
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\n" ); document.write( "e + y = 30
\n" ); document.write( "e = y^2
\n" ); document.write( "---> 5 & 25 then
\n" ); document.write( "9 & 29 now
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\n" ); document.write( "The hard way:
\n" ); document.write( "e + y = 30
\n" ); document.write( "e = y^2
\n" ); document.write( "y^2 + y - 30 = 0
\n" ); document.write( "(y+6)*(y-5) = 0
\n" ); document.write( "y = 5
\n" ); document.write( "etc
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