document.write( "Question 1163114: Jennifer drove 300 miles to see her friend. On the return trip, she drove 10 mph faster, so she made the return trip in 1 hour less time. What was her speed on the way to friend's home. \n" ); document.write( "
Algebra.Com's Answer #787103 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Jennifer drove 300 miles to see her friend. On the return trip, she drove 10 mph faster, so she made the return trip in 1 hour less time. What was her speed on the way to friend's home.
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Let speed on outbound leg be S
\n" ); document.write( "Then speed on return leg = S + 10
\n" ); document.write( "We then get the following TIME equation: \"matrix%281%2C3%2C+300%2FS%2C+%22=%22%2C+300%2F%28S+%2B+10%29+%2B+1%29\"
\n" ); document.write( "300(S + 10) = 300S + S(S + 10) ------ Multiplying by LCD, S(S + 10)
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\n" ); document.write( "0 = (S - 50)(S + 60)
\n" ); document.write( "S - 50 = 0 OR S + 60 = 0
\n" ); document.write( "Speed on outbound leg, or \"highlight_green%28matrix%281%2C4%2C+S%2C+%22=%22%2C+50%2C+mph%29%29\" OR S = - 60 (ignore) \n" ); document.write( "
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