document.write( "Question 1163109: I don't know how to answer this because as far as I know this is not factorable, but the question seems to say that it is.\r
\n" ); document.write( "\n" ); document.write( "David’s homework was to factor the polynomial completely (a) over the real numbers, (b) over the complex numbers.\r
\n" ); document.write( "\n" ); document.write( "x^3+4x^2+5x\r
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\n" ); document.write( "\n" ); document.write( "He started x(x^2+4x+5) He knows that x=0 is a real root.
\n" ); document.write( "But there are no real factors of 5 that add up to 4???? So what does he do?
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Algebra.Com's Answer #787088 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "At the point where you have

\n" ); document.write( "\"x%5E3%2B4x%5E2%2B45+=+x%28x%5E2%2B4x%2B5%29\"

\n" ); document.write( "you are finished with part (a); the remaining quadratic factor does not factor over the real numbers.

\n" ); document.write( "However, every quadratic expression factors over the complex numbers; so you can do part (b). Solve the equation

\n" ); document.write( "\"x%5E2%2B4x%2B5+=+0\"

\n" ); document.write( "using the quadratic formula. That gives you the roots of the quadratic equation; therefore it shows you how to factor the quadratic over the complex numbers.

\n" ); document.write( "\"x+=+%28-4+%2B+sqrt%2816-20%29%29%2F2+=+-2%2Bi\"

\n" ); document.write( "and

\n" ); document.write( "\"x+=+%28-4+-+sqrt%2816-20%29%29%2F2+=+-2-i\"

\n" ); document.write( "So

\n" ); document.write( "\"x%5E2%2B4x%2B5+=+%28x-%28-2%2Bi%29%29%28x-%28-2-i%29%29\"

\n" ); document.write( "And so, finally,

\n" ); document.write( "\"x%5E3%2B4x%5E2%2B5x+=+%28x%29%28x-%28-2%2Bi%29%29%28x-%28-2-i%29%29\"

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