document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163099>Question 1163099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP!!!!!!!!!!<BR>\n" );
document.write( "Consider the following hypotheses:\r<BR>\n" );
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document.write( "H0: p ≥ 0.47\r<BR>\n" );
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document.write( "HA: p < 0.47\r<BR>\n" );
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document.write( "Compute the p-value based on the following sample information. (You may find it useful to reference the appropriate table: z table or t table) (Round \"z\" value to 2 decimal places. Round intermediate calculations to at least 4 decimal places and final answers to 4 decimal places.)\r<BR>\n" );
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document.write( "  	  	          p-value<BR>\n" );
document.write( "a. x = 46; n = 118 	  _______ 		 <BR>\n" );
document.write( "b. x = 112; n = 311 	  _______ 		 <BR>\n" );
document.write( "c. p¯ = 0.38; n = 53 	  _______		 <BR>\n" );
document.write( "d. p¯ = 0.38; n = 430 	  _______		 \r<BR>\n" );
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document.write( "THANK YOU VERY MUCH!!!!!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #787072 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=787072\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p hat=46/118=0.3898<BR>\n" );
document.write( "z=(0.39-0.47)/sqrt(0.47*0.53/118). use the hypothesized p and 1-p, not the sample<BR>\n" );
document.write( "=-0.0802/0.0459<BR>\n" );
document.write( "=-1.7473<BR>\n" );
document.write( "use probability that z<=1.7412 as a one way test.  That is 0.0403\r<BR>\n" );
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document.write( "b has p hat=0.3601<BR>\n" );
document.write( "z=-0.1099/sqrt(.47*.53/311)<BR>\n" );
document.write( "=3.8832<BR>\n" );
document.write( "p<0.0001\r<BR>\n" );
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document.write( "Try doing c and d using z=(0.38-0.47)/sqrt(0.47*0.53/53) and denominator of 430 for d.<BR>\n" );
document.write( "then finding the probability of z to the left of that value.  That is your p-value<BR>\n" );
document.write( "c will have a fairly high p-value because of the smaller sample size<BR>\n" );
document.write( "d will have a small p-value </SPAN>\n" );
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