document.write( "Question 1163068: PLEASE HELP!!!!!!!!!!!
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document.write( "In a recent poll of 1,600 homeowners in the United States, one in eight homeowners reports having a home equity loan that he or she is currently paying off. Using a confidence coefficient of 0.99, derive the interval estimate for the proportion of all homeowners in the United States that hold a home equity loan. (You may find it useful to reference the z table. Round intermediate calculations to at least 4 decimal places. Round \"z\" value and final answers to 3 decimal places.) \r
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document.write( "Thank you very much for your help!! \n" );
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Algebra.Com's Answer #787027 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! half-interval for a 99% CI is z(0.995)*sqrt(p*(1-p)/n. p=1/8 1-p=7/8 and their product is 1/64 \n" ); document.write( "sqrt term is sqrt(7/64)/sqrt(1600)=sqrt(7)/8*40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "=2.576*(sqrt(7/64))/40 \n" ); document.write( "=2.576*sqrt(7)/320 \n" ); document.write( "=0.0213 \n" ); document.write( "interval is 1/8+/-0.0213 \n" ); document.write( "(0.1037, 0.1463) or (0.104, 0.146) \n" ); document.write( " |