document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1163056>Question 1163056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the shaded segment of circle O to the nearest tenth of a square unit. The radius of the circle is 6 units. The perpendicular from O to the chord joining point A to point B measures 4 units. This Is the link to the diagram. https://drive.google.com/file/d/1-nFHdeNhm8pyfkVN1HXpfg6ckeoBaM7b/view?usp=drivesdk </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #787015 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=787015\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of the shaded segment of circle O to the nearest tenth of a square unit. The radius of the circle is 6 units. <BR>\n" );
document.write( "The perpendicular from O to the chord joining point A to point B measures 4 units.<BR>\n" );
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document.write( "Find the area of the circle:<BR>\n" );
document.write( "A  = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A6%5E2 ALIGN=MIDDLE  ALT=\"pi%2A6%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A = 113.1 sq/units<BR>\n" );
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document.write( "Find the arc angle using the cosine of the two right triangles <BR>\n" );
document.write( "cos(C) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2F6 ALIGN=MIDDLE  ALT=\"4%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "C = 48.2 degrees<BR>\n" );
document.write( "The arc angle: 2 * 48.2 = 96.4 degrees<BR>\n" );
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document.write( "Find area of the given arc<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=96.4%2F360 ALIGN=MIDDLE  ALT=\"96.4%2F360\"   DISABLED_style= \"max-width:90%; height:auto;\" > * 113.1 = 30.3 sq/units<BR>\n" );
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document.write( "Find the area of the two right triangles<BR>\n" );
document.write( "find the base (b) of the triangle using the sine of 48.2<BR>\n" );
document.write( "sin(48.2) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%2F6 ALIGN=MIDDLE  ALT=\"b%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "b = sin(48.2) * 6<BR>\n" );
document.write( "b = 4.47 units<BR>\n" );
document.write( "Find the area<BR>\n" );
document.write( "A = .5*4.47*4<BR>\n" );
document.write( "A = 8.9 sq/units<BR>\n" );
document.write( "2 * 8.9 = 17.9 sq/units the area of the 2 right triangles<BR>\n" );
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document.write( "Find f<BR>\n" );
document.write( "subtract area of the two right triangle from the arc area<BR>\n" );
document.write( "30.3 - 17.9 = 12.4 sq/units the area of f<BR>\n" );
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