document.write( "Question 1163040: If the series {ak} satisfies that a1 = 1, and a2 = 2, and ak - 4a(k-1) + 3a(k-2) = 0 (k >= 0), then ak = (1 + p)/q. Find p and q for all values of k >= 1. \n" ); document.write( "
Algebra.Com's Answer #786996 by ikleyn(52790)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A short notice.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The recursive formula in the post determines the sequence, which is not a constant.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " It is almost OBVIOUS.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "But the formula \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, it is CLEAR that there is an ERROR in your post, which makes it incorrect.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Look into your source and find the error.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then re-post to the forum.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you do, please do not re-post to me personally.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |