document.write( "Question 1163013: In a round robin competition, everyone plays everyone else at least once. How
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Algebra.Com's Answer #786950 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "To be correct, the problem should be formulated in DIFFERENT WAY:\r
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document.write( "    In a round robin competition, everyone plays everyone else  exactly one time. \r\n" );
document.write( "    How many games would be played if there were six players? \r\n" );
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document.write( "    How many more games would be needed if three extra players entered the competition?\r\n" );
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\n" ); document.write( "\n" ); document.write( "Then the answer to the first question is    $\"%286%2A5%29%2F2\"$ = 3*5 = 15 games.\r
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\n" ); document.write( "\n" ); document.write( "The answer to the second question is    $\"%289%2A8%29%2F2\"$ - 15 = 9*4 - 15 = 36 - 15 = 21 games   (the difference).
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\n" ); document.write( "\n" ); document.write( "For n participants, the number of games between them is    $\"%28n%2A%28n-1%29%29%2F2\"$ .\r
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