document.write( "Question 1162990: Sally walked to the store from her home at the rate of 5 miles per hour. After spending one-half hour in the store, her friend gave her a ride home at the rate of 30 miles per hour. She arrived home 1 hour and 5 minutes (1 1/12 hours) after she left from home. How far is the store from Sally’s home? \n" ); document.write( "
Algebra.Com's Answer #786927 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is an alternative method for solving a problem like this, if a formal algebraic solution is not required. \n" ); document.write( "For me, this alternative method is much faster than using formal algebra to write and solve an equation. \n" ); document.write( "The time spent driving is the total time of 1 1/12 hours, minus the 1/2 hour she spent in the store; that is 7/12 of an hour. \n" ); document.write( "The ratio of the walking and riding speeds is 1:6; so the amounts of time walking and riding are in the ratio 6:1. \n" ); document.write( "That means 6/7 of the total travel time was walking and 1/7 of it was riding. That means 6/12 = 1/2 hour walking and 1/12 hour riding. \n" ); document.write( "The distance to the store is (1/2 hour)*(5mph) = 2.5 miles. \n" ); document.write( "or... \n" ); document.write( "The distance to the store is (1/12 hour)*(30mph) = 2.5 miles. \n" ); document.write( " \n" ); document.write( " |