document.write( "Question 107969: Solve the system of equations using the addition (elimination) method.
\n" ); document.write( "If the answer is a unique solution, present it as an ordered pair: (x, y). If not, specify whether the answer is “no solution” or “infinitely many solutions.”
\n" ); document.write( "9x + 2y = 2
\n" ); document.write( "3x + 5y = 5
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Algebra.Com's Answer #78681 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"9%2Ax%2B2%2Ay=2\"
\n" ); document.write( " \"3%2Ax%2B5%2Ay=5\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 9 and 3 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 9 and 3 is 9, we need to multiply both sides of the top equation by 1 and multiply both sides of the bottom equation by -3 like this:
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\n" ); document.write( " \"1%2A%289%2Ax%2B2%2Ay%29=%282%29%2A1\" Multiply the top equation (both sides) by 1
\n" ); document.write( " \"-3%2A%283%2Ax%2B5%2Ay%29=%285%29%2A-3\" Multiply the bottom equation (both sides) by -3
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"9%2Ax%2B2%2Ay=2\"
\n" ); document.write( " \"-9%2Ax-15%2Ay=-15\"
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\n" ); document.write( " Notice how 9 and -9 add to zero (ie \"9%2B-9=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%289%2Ax-9%2Ax%29%2B%282%2Ay-15%2Ay%29=2-15\"
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\n" ); document.write( " \"%289-9%29%2Ax%2B%282-15%29y=2-15\"
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\n" ); document.write( " \"cross%289%2B-9%29%2Ax%2B%282-15%29%2Ay=2-15\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-13%2Ay=-13\"
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\n" ); document.write( " \"y=-13%2F-13\" Divide both sides by \"-13\" to solve for y
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\n" ); document.write( " \"y=1\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"9%2Ax%2B2%2Ay=2\" to solve for x
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\n" ); document.write( " \"9%2Ax%2B2%281%29=2\" Plug in \"y=1\"
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\n" ); document.write( " \"9%2Ax%2B2=2\" Multiply
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\n" ); document.write( " \"9%2Ax=2-2\" Subtract \"2\" from both sides
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\n" ); document.write( " \"9%2Ax=0\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F9%29%289%29%29%2Ax=%280%29%281%2F9%29\" Multiply both sides by \"1%2F9\". This will cancel out \"9\" on the left side.
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\n" ); document.write( " \"x=0\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=0\", \"y=1\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"0\", \"1\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"9%2Ax%2B2%2Ay=2\"
\n" ); document.write( " \"3%2Ax%2B5%2Ay=5\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"9%2Ax%2B2%2Ay=2\" (red) \"3%2Ax%2B5%2Ay=5\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"0\",\"1\"). This verifies our answer.
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