document.write( "Question 1162873: You need a 40% alcohol solution. On hand, you have a 160 mL of a 50% alcohol mixture. How much pure water will you need to add to obtain the desired solution?\r
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document.write( "You will need
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document.write( " __ mL of pure water to obtain
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document.write( " __ mL of the desired 40% solution. \n" );
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Algebra.Com's Answer #786778 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 160 ml*0.50 alcohol is 80 ml pure alcohol wanted in final solution \n" ); document.write( "add x ml water \n" ); document.write( "now have (160+x)*(0.40)=80 ml pure alcohol \n" ); document.write( "64+0.40x=80 \n" ); document.write( "0.40x=16 ml \n" ); document.write( "x=40 ml of water ANSWER \n" ); document.write( "that will give 200 ml of solution of 40% or 80 ml pure alcohol. ANSWER \n" ); document.write( " |