document.write( "Question 1162832: x^2 - 2x +1 - 100y^4 = ?\r
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\n" ); document.write( "a) (100y^2 + x - 1)(-100y^2 + x - 1)
\n" ); document.write( "b) (x^2 - 3x)(1 - 100y^4)
\n" ); document.write( "c) (3x + 1)(x^2 - 100y^4)
\n" ); document.write( "d) x(x-3) -1(1 - 100y^4) \n" ); document.write( "
Algebra.Com's Answer #786741 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "x^2 - 2x +1 - 100y^4 = ?\r\n" );
document.write( "Answer Choices:\r\n" );
document.write( "a) (100y^2 + x - 1)(-100y^2 + x - 1)\r\n" );
document.write( "b) (x^2 - 3x)(1 - 100y^4)\r\n" );
document.write( "c) (3x + 1)(x^2 - 100y^4)\r\n" );
document.write( "d) x(x-3) -1(1 - 100y^4)\r\n" );
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document.write( "Oh phooey! Greenstamps did it for you.  I was going to do another one\r\n" );
document.write( "exactly like it, only with different numbers so you couldn't get credit for\r\n" );
document.write( "what somebody else did.  Anyway here's the one that was exactly like it that\r\n" );
document.write( "I was going to give you.\r\n" );
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document.write( "x2 - 4x + 4 - 25y4\r\n" );
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document.write( "Factor the first three terms:\r\n" );
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document.write( "(x - 2)(x - 2) - 25y4\r\n" );
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document.write( "Since the first factorization has both factors equal, write\r\n" );
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document.write( "it as one of them squared:\r\n" );
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document.write( "(x - 2)2 - 25y4\r\n" );
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document.write( "That factors as the difference of two squares.\r\n" );
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document.write( "[(x - 2) - 5y][(x - 2) + 5y]\r\n" );
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document.write( "Remove the parentheses inside the brackets:\r\n" );
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document.write( "[x - 2 - 5y][x - 2 + 5y]\r\n" );
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document.write( "Rearrange the terms so that the constant terms come last,\r\n" );
document.write( "and the letter terms are first in alphabetical order.  Also\r\n" );
document.write( "change the brackets to parentheses\r\n" );
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document.write( "(x - 5y - 2)(x + 5y - 2)\r\n" );
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document.write( "Edwin

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