document.write( "Question 1162839: When 347 college students are randomly selected and surveyed, it is found that 117 own a car. Find a 99% confidence interval for the true proportion of all college students who own a car. \n" ); document.write( "
Algebra.Com's Answer #786738 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! half-interval for 99% CI is z(0.995)*sqrt (p(1-p)/n), where p=117/347 or 0.337 \n" ); document.write( "z is 2.576 \n" ); document.write( "sqrt term is 0.0254 \n" ); document.write( "half-interval is that product or 0.0654 \n" ); document.write( "add to and subtract that from mean \n" ); document.write( "(0.272, 0.402) \n" ); document.write( " |