document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1162826>Question 1162826</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You need 665 mL of a 65% alcohol solution. On hand, you have a 95% alcohol mixture. How much of the 95% alcohol mixture and pure water will you need to obtain the desired solution?\r<BR>\n" );
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document.write( "You will need<BR>\n" );
document.write( " ? mL of pure water<BR>\n" );
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document.write( " ? mL of the 95% solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #786706 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=786706\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  x  be the volume of the pure water under the question, in mL.\r<BR>\n" );
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document.write( "Then the volume of the pure alcohol in 140 mL of the 65% alcohol solution is  0.65*140 mL.\r<BR>\n" );
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document.write( "The total volume after adding x mL of water is (140+x) mL.\r<BR>\n" );
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document.write( "The concentration equation for the resulting mixture after adding water is\r<BR>\n" );
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document.write( "    %280.65%2A140%29%2F%28140%2Bx%29 = 0.35.\r<BR>\n" );
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document.write( "From the equation, \r<BR>\n" );
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document.write( "    0.065*140 = 0.35*(140+x)\r<BR>\n" );
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document.write( "    0.065*140 = 0.35*140 + 0.35x\r<BR>\n" );
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document.write( "    x = %28065%2A140+-+0.35%2A140%29%2F0.35 = 120 mL.\r<BR>\n" );
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document.write( "ANSWER.  120 mL of water should be added.\r<BR>\n" );
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document.write( "Same problem, different numbers.<BR>\n" );
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