document.write( "Question 1162779: A collection of nickels, dimes, and quarters consist of 8 coins with a total of $1.30. If the number of dimes is equal to the number of nickels, find the number of each type of coins. \n" ); document.write( "
Algebra.Com's Answer #786634 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let n = no. of nickels \n" ); document.write( "let d = no. of dimes \n" ); document.write( "let q = no. of quarters \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( " A collection of nickels, dimes, and quarters consist of 8 coins \n" ); document.write( "n + d + q = 8 \n" ); document.write( " with a total of $1.30. \n" ); document.write( ".05 + .10d + .25 = 1.30 \n" ); document.write( "If the number of dimes is equal to the number of nickels, \n" ); document.write( "d = n \n" ); document.write( ": \n" ); document.write( "multiply the 2nd equation by 4 and subtract from the 1st equation \n" ); document.write( " 1n + 1d + 1q = 8 \n" ); document.write( ".2n + .4d + 1q = 5.20 \n" ); document.write( "----------------------subtraction eliminates q \n" ); document.write( ".8n + .6d = 2.80 \n" ); document.write( "d = n, therefore \n" ); document.write( ".8n + .6n = 2.80 \n" ); document.write( "1.4n = 2.80 \n" ); document.write( "n = 2.8/1.4 \n" ); document.write( "n = 2 nickels \n" ); document.write( "then since d = n \n" ); document.write( "d = 2 dimes \n" ); document.write( "and \n" ); document.write( "q = 8 - 2 - 2 \n" ); document.write( "q = 4 quarters \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out \n" ); document.write( ".05(2) + .10(2) + .25(4) = \n" ); document.write( ".10 + .20 + 1.00 = 1.30 \n" ); document.write( " \n" ); document.write( " |